Integrand size = 22, antiderivative size = 556 \[ \int \frac {1}{x^4 \sqrt [3]{1-x^2} \left (3+x^2\right )} \, dx=-\frac {\left (1-x^2\right )^{2/3}}{9 x^3}-\frac {2 \left (1-x^2\right )^{2/3}}{27 x}+\frac {2 x}{27 \left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )}+\frac {\arctan \left (\frac {\sqrt {3}}{x}\right )}{18\ 2^{2/3} \sqrt {3}}+\frac {\arctan \left (\frac {\sqrt {3} \left (1-\sqrt [3]{2} \sqrt [3]{1-x^2}\right )}{x}\right )}{18\ 2^{2/3} \sqrt {3}}-\frac {\text {arctanh}(x)}{54\ 2^{2/3}}+\frac {\text {arctanh}\left (\frac {x}{1+\sqrt [3]{2} \sqrt [3]{1-x^2}}\right )}{18\ 2^{2/3}}+\frac {\sqrt {2+\sqrt {3}} \left (1-\sqrt [3]{1-x^2}\right ) \sqrt {\frac {1+\sqrt [3]{1-x^2}+\left (1-x^2\right )^{2/3}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}} E\left (\arcsin \left (\frac {1+\sqrt {3}-\sqrt [3]{1-x^2}}{1-\sqrt {3}-\sqrt [3]{1-x^2}}\right )|-7+4 \sqrt {3}\right )}{9\ 3^{3/4} x \sqrt {-\frac {1-\sqrt [3]{1-x^2}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}}}-\frac {2 \sqrt {2} \left (1-\sqrt [3]{1-x^2}\right ) \sqrt {\frac {1+\sqrt [3]{1-x^2}+\left (1-x^2\right )^{2/3}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {1+\sqrt {3}-\sqrt [3]{1-x^2}}{1-\sqrt {3}-\sqrt [3]{1-x^2}}\right ),-7+4 \sqrt {3}\right )}{27 \sqrt [4]{3} x \sqrt {-\frac {1-\sqrt [3]{1-x^2}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}}} \]
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Time = 0.22 (sec) , antiderivative size = 556, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.364, Rules used = {491, 597, 544, 241, 310, 225, 1893, 402} \[ \int \frac {1}{x^4 \sqrt [3]{1-x^2} \left (3+x^2\right )} \, dx=-\frac {2 \sqrt {2} \left (1-\sqrt [3]{1-x^2}\right ) \sqrt {\frac {\left (1-x^2\right )^{2/3}+\sqrt [3]{1-x^2}+1}{\left (-\sqrt [3]{1-x^2}-\sqrt {3}+1\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {-\sqrt [3]{1-x^2}+\sqrt {3}+1}{-\sqrt [3]{1-x^2}-\sqrt {3}+1}\right ),-7+4 \sqrt {3}\right )}{27 \sqrt [4]{3} \sqrt {-\frac {1-\sqrt [3]{1-x^2}}{\left (-\sqrt [3]{1-x^2}-\sqrt {3}+1\right )^2}} x}+\frac {\sqrt {2+\sqrt {3}} \left (1-\sqrt [3]{1-x^2}\right ) \sqrt {\frac {\left (1-x^2\right )^{2/3}+\sqrt [3]{1-x^2}+1}{\left (-\sqrt [3]{1-x^2}-\sqrt {3}+1\right )^2}} E\left (\arcsin \left (\frac {-\sqrt [3]{1-x^2}+\sqrt {3}+1}{-\sqrt [3]{1-x^2}-\sqrt {3}+1}\right )|-7+4 \sqrt {3}\right )}{9\ 3^{3/4} \sqrt {-\frac {1-\sqrt [3]{1-x^2}}{\left (-\sqrt [3]{1-x^2}-\sqrt {3}+1\right )^2}} x}+\frac {\arctan \left (\frac {\sqrt {3} \left (1-\sqrt [3]{2} \sqrt [3]{1-x^2}\right )}{x}\right )}{18\ 2^{2/3} \sqrt {3}}+\frac {\arctan \left (\frac {\sqrt {3}}{x}\right )}{18\ 2^{2/3} \sqrt {3}}+\frac {\text {arctanh}\left (\frac {x}{\sqrt [3]{2} \sqrt [3]{1-x^2}+1}\right )}{18\ 2^{2/3}}-\frac {\text {arctanh}(x)}{54\ 2^{2/3}}+\frac {2 x}{27 \left (-\sqrt [3]{1-x^2}-\sqrt {3}+1\right )}-\frac {2 \left (1-x^2\right )^{2/3}}{27 x}-\frac {\left (1-x^2\right )^{2/3}}{9 x^3} \]
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Rule 225
Rule 241
Rule 310
Rule 402
Rule 491
Rule 544
Rule 597
Rule 1893
Rubi steps \begin{align*} \text {integral}& = -\frac {\left (1-x^2\right )^{2/3}}{9 x^3}+\frac {1}{9} \int \frac {2+\frac {5 x^2}{3}}{x^2 \sqrt [3]{1-x^2} \left (3+x^2\right )} \, dx \\ & = -\frac {\left (1-x^2\right )^{2/3}}{9 x^3}-\frac {2 \left (1-x^2\right )^{2/3}}{27 x}-\frac {1}{27} \int \frac {-1+\frac {2 x^2}{3}}{\sqrt [3]{1-x^2} \left (3+x^2\right )} \, dx \\ & = -\frac {\left (1-x^2\right )^{2/3}}{9 x^3}-\frac {2 \left (1-x^2\right )^{2/3}}{27 x}-\frac {2}{81} \int \frac {1}{\sqrt [3]{1-x^2}} \, dx+\frac {1}{9} \int \frac {1}{\sqrt [3]{1-x^2} \left (3+x^2\right )} \, dx \\ & = -\frac {\left (1-x^2\right )^{2/3}}{9 x^3}-\frac {2 \left (1-x^2\right )^{2/3}}{27 x}+\frac {\tan ^{-1}\left (\frac {\sqrt {3}}{x}\right )}{18\ 2^{2/3} \sqrt {3}}+\frac {\tan ^{-1}\left (\frac {\sqrt {3} \left (1-\sqrt [3]{2} \sqrt [3]{1-x^2}\right )}{x}\right )}{18\ 2^{2/3} \sqrt {3}}-\frac {\tanh ^{-1}(x)}{54\ 2^{2/3}}+\frac {\tanh ^{-1}\left (\frac {x}{1+\sqrt [3]{2} \sqrt [3]{1-x^2}}\right )}{18\ 2^{2/3}}+\frac {\sqrt {-x^2} \text {Subst}\left (\int \frac {x}{\sqrt {-1+x^3}} \, dx,x,\sqrt [3]{1-x^2}\right )}{27 x} \\ & = -\frac {\left (1-x^2\right )^{2/3}}{9 x^3}-\frac {2 \left (1-x^2\right )^{2/3}}{27 x}+\frac {\tan ^{-1}\left (\frac {\sqrt {3}}{x}\right )}{18\ 2^{2/3} \sqrt {3}}+\frac {\tan ^{-1}\left (\frac {\sqrt {3} \left (1-\sqrt [3]{2} \sqrt [3]{1-x^2}\right )}{x}\right )}{18\ 2^{2/3} \sqrt {3}}-\frac {\tanh ^{-1}(x)}{54\ 2^{2/3}}+\frac {\tanh ^{-1}\left (\frac {x}{1+\sqrt [3]{2} \sqrt [3]{1-x^2}}\right )}{18\ 2^{2/3}}-\frac {\sqrt {-x^2} \text {Subst}\left (\int \frac {1+\sqrt {3}-x}{\sqrt {-1+x^3}} \, dx,x,\sqrt [3]{1-x^2}\right )}{27 x}+\frac {\left (\left (1+\sqrt {3}\right ) \sqrt {-x^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {-1+x^3}} \, dx,x,\sqrt [3]{1-x^2}\right )}{27 x} \\ & = -\frac {\left (1-x^2\right )^{2/3}}{9 x^3}-\frac {2 \left (1-x^2\right )^{2/3}}{27 x}+\frac {2 x}{27 \left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )}+\frac {\tan ^{-1}\left (\frac {\sqrt {3}}{x}\right )}{18\ 2^{2/3} \sqrt {3}}+\frac {\tan ^{-1}\left (\frac {\sqrt {3} \left (1-\sqrt [3]{2} \sqrt [3]{1-x^2}\right )}{x}\right )}{18\ 2^{2/3} \sqrt {3}}-\frac {\tanh ^{-1}(x)}{54\ 2^{2/3}}+\frac {\tanh ^{-1}\left (\frac {x}{1+\sqrt [3]{2} \sqrt [3]{1-x^2}}\right )}{18\ 2^{2/3}}+\frac {\sqrt {2+\sqrt {3}} \left (1-\sqrt [3]{1-x^2}\right ) \sqrt {\frac {1+\sqrt [3]{1-x^2}+\left (1-x^2\right )^{2/3}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}} E\left (\sin ^{-1}\left (\frac {1+\sqrt {3}-\sqrt [3]{1-x^2}}{1-\sqrt {3}-\sqrt [3]{1-x^2}}\right )|-7+4 \sqrt {3}\right )}{9\ 3^{3/4} x \sqrt {-\frac {1-\sqrt [3]{1-x^2}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}}}-\frac {2 \sqrt {2} \left (1-\sqrt [3]{1-x^2}\right ) \sqrt {\frac {1+\sqrt [3]{1-x^2}+\left (1-x^2\right )^{2/3}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}} F\left (\sin ^{-1}\left (\frac {1+\sqrt {3}-\sqrt [3]{1-x^2}}{1-\sqrt {3}-\sqrt [3]{1-x^2}}\right )|-7+4 \sqrt {3}\right )}{27 \sqrt [4]{3} x \sqrt {-\frac {1-\sqrt [3]{1-x^2}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}}} \\ \end{align*}
Result contains higher order function than in optimal. Order 6 vs. order 4 in optimal.
Time = 10.09 (sec) , antiderivative size = 166, normalized size of antiderivative = 0.30 \[ \int \frac {1}{x^4 \sqrt [3]{1-x^2} \left (3+x^2\right )} \, dx=-\frac {2}{729} x^3 \operatorname {AppellF1}\left (\frac {3}{2},\frac {1}{3},1,\frac {5}{2},x^2,-\frac {x^2}{3}\right )+\frac {-3+x^2+2 x^4-\frac {9 x^4 \operatorname {AppellF1}\left (\frac {1}{2},\frac {1}{3},1,\frac {3}{2},x^2,-\frac {x^2}{3}\right )}{\left (3+x^2\right ) \left (-9 \operatorname {AppellF1}\left (\frac {1}{2},\frac {1}{3},1,\frac {3}{2},x^2,-\frac {x^2}{3}\right )+2 x^2 \left (\operatorname {AppellF1}\left (\frac {3}{2},\frac {1}{3},2,\frac {5}{2},x^2,-\frac {x^2}{3}\right )-\operatorname {AppellF1}\left (\frac {3}{2},\frac {4}{3},1,\frac {5}{2},x^2,-\frac {x^2}{3}\right )\right )\right )}}{27 x^3 \sqrt [3]{1-x^2}} \]
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\[\int \frac {1}{x^{4} \left (-x^{2}+1\right )^{\frac {1}{3}} \left (x^{2}+3\right )}d x\]
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\[ \int \frac {1}{x^4 \sqrt [3]{1-x^2} \left (3+x^2\right )} \, dx=\int { \frac {1}{{\left (x^{2} + 3\right )} {\left (-x^{2} + 1\right )}^{\frac {1}{3}} x^{4}} \,d x } \]
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\[ \int \frac {1}{x^4 \sqrt [3]{1-x^2} \left (3+x^2\right )} \, dx=\int \frac {1}{x^{4} \sqrt [3]{- \left (x - 1\right ) \left (x + 1\right )} \left (x^{2} + 3\right )}\, dx \]
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\[ \int \frac {1}{x^4 \sqrt [3]{1-x^2} \left (3+x^2\right )} \, dx=\int { \frac {1}{{\left (x^{2} + 3\right )} {\left (-x^{2} + 1\right )}^{\frac {1}{3}} x^{4}} \,d x } \]
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\[ \int \frac {1}{x^4 \sqrt [3]{1-x^2} \left (3+x^2\right )} \, dx=\int { \frac {1}{{\left (x^{2} + 3\right )} {\left (-x^{2} + 1\right )}^{\frac {1}{3}} x^{4}} \,d x } \]
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Timed out. \[ \int \frac {1}{x^4 \sqrt [3]{1-x^2} \left (3+x^2\right )} \, dx=\int \frac {1}{x^4\,{\left (1-x^2\right )}^{1/3}\,\left (x^2+3\right )} \,d x \]
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